Fresh from his participation at the Mubadala World Tennis Championship in Abu Dhabi, world No 4 Stan Wawrinka will head to India for the ATP Chennai Open, starting Monday, in preparation for the Australian Open later this month.
The French Open champion, who reached the semi-finals in Abu Dhabi before being ousted by Milos Raonic, is bidding for his third consecutive Chennai Open title and hopes a victory in India will help propel him to another major win, just as it did in 2014 and 2015.
Two years ago Wawrinka clinched his first grand slam when he won the Australian Open just weeks after triumphing in southern India. Last year, Wawrinka followed up victory in Chennai by taking home the trophy at Roland Garros in June.
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“I’ve always enjoyed coming to Chennai. The tournament is a nice way to start the season, the fans are great and I like the atmosphere in the stadium,” Wawrinka said.
“2015 has been an amazing year and 2016 is already around the corner. I want to continue to do well, win tournaments, and go deep at the Slams. And hopefully I get a great start into the season in Chennai again.”
Wawrinka also won in Chennai in 2011 and is the top seed in the $480,000 tournament.
His closest challenger is likely to be number two seed Kevin Anderson. The big-serving South African has a 4-4 record against Wawrinka but says he’s not thinking too much about his opponents.
“I typically try to focus on my own game and I know if I do that and execute, I can beat anyone,” said the world number 12.
The final of the Chennai Open takes place on Sunday.
The Australian Open in Melbourne runs from January 18 to 31.
Seedings:
1. Stanislas Wawrinka (SUI)
2. Kevin Anderson (RSA)
3. Benoit Paire (FRA)
4. Roberto Bautista Agut (ESP)
5. Guillermo Garcia-Lopez (ESP)
6. Gilles Muller (LUX)
7. Vasek Pospisil (CAN)
8. Borna Coric (CRO)
